3[x+2]+3[x-2]=

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Solution for 3[x+2]+3[x-2]= equation:


Simplifying
3[x + 2] + 3[x + -2] = 0

Reorder the terms:
3[2 + x] + 3[x + -2] = 0
[2 * 3 + x * 3] + 3[x + -2] = 0
[6 + 3x] + 3[x + -2] = 0

Reorder the terms:
6 + 3x + 3[-2 + x] = 0
6 + 3x + [-2 * 3 + x * 3] = 0
6 + 3x + [-6 + 3x] = 0

Reorder the terms:
6 + -6 + 3x + 3x = 0

Combine like terms: 6 + -6 = 0
0 + 3x + 3x = 0
3x + 3x = 0

Combine like terms: 3x + 3x = 6x
6x = 0

Solving
6x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Divide each side by '6'.
x = 0

Simplifying
x = 0

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